13x^2+9x+1=0

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Solution for 13x^2+9x+1=0 equation: 



13x^2+9x+1=0

a = 13; b = 9; c = +1;
Δ = b2-4ac
Δ = 92-4·13·1
Δ = 29
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{29}}{2*13}=\frac{-9-\sqrt{29}}{26}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{29}}{2*13}=\frac{-9+\sqrt{29}}{26}
$

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